We have a question:
X'={{1,0,0} {-4,1,0} {3,6,2}}X; X(0)={-1,2,-30}
I have worked out to the general solution but I don't think it's right. I have:
X=C1 {0,0,1}e^2t + C2 {0,-1,6} e^t + C3 [{0,-2,6} + {0,-1,6}t] e^t
this gives me x(t)=0....
2 answers
hmmm. There do seem to be too many zeros to make things work out right.
However, at
http://www.wolframalpha.com/widgets/gallery/view.jsp?id=ef7f9b7e172cd67fb8f192f29fc1e483
it gets a solution apparently involving eigenvalues -1 and 3
http://www.wolframalpha.com/widgets/gallery/view.jsp?id=ef7f9b7e172cd67fb8f192f29fc1e483
it gets a solution apparently involving eigenvalues -1 and 3