We drop 37.4 grams of magnesium into
461 mL of a 3 M HCl solution. What is
the maximum volume of dry hydrogen that
could be produced by this reaction at STP?
Mg(s) + 2HCl(aq) ! MgCl2(aq) + H2(g)
Answer in units of liters
461 mL of a 3 M HCl solution. What is
the maximum volume of dry hydrogen that
could be produced by this reaction at STP?
Mg(s) + 2HCl(aq) ! MgCl2(aq) + H2(g)
Answer in units of liters