We are interested in calculating the probability that there are 5 Heads in the first 6 tosses and 3 Heads in the last 5 tosses. Give the exact numerical values of a , b , c , d that would match the answer ap7(1−p)3+bpc(1−p)d.

Answer 1

prob(5 heads in 6 tosses and 3 heads in next 5 tosses)
= C(6,5) (1/2)^5 (1/2) * C(5,3) (1/2)^3 (1/2)^2
= 6*10 *(1/2)^11

what does ap7(1−p)3+bpc(1−p)d mean?
perhaps: ap^7 (1−p)^ 3 + bp^c (1−p)^d