Asked by Alex
We are going to compute the cube root of 9 to 6 significant digits using Newton's method.
Choose a function of the form
š(š„)=(š„^š)āš¶
Give the formula for š„_(š+1) in terms of the previous value š„_(š) .
Choose a function of the form
š(š„)=(š„^š)āš¶
Give the formula for š„_(š+1) in terms of the previous value š„_(š) .
Answers
Answered by
oobleck
you want y = x^3 - 9
Now just apply Newton's method, which I'm sure you can find
(a) in your text
(b) online.
It doesn't even really matter how close your first guess is, since it converges quite rapidly (if at all, but x^3 is a nice well-behaved function).
Now just apply Newton's method, which I'm sure you can find
(a) in your text
(b) online.
It doesn't even really matter how close your first guess is, since it converges quite rapidly (if at all, but x^3 is a nice well-behaved function).
Answered by
Reiny
Here is my simplistic GWBASIC program (from the early 80's)
10 x = 2
20 xnew = x - (x^3 - 9)/(3*x^2)
30 if ABS(xnew - x) < .0000001 THEN END
40 PRINT XNEW
50 X = XNEW
60 GOTO 20
2.083333
2.080089
2.080084
10 x = 2
20 xnew = x - (x^3 - 9)/(3*x^2)
30 if ABS(xnew - x) < .0000001 THEN END
40 PRINT XNEW
50 X = XNEW
60 GOTO 20
2.083333
2.080089
2.080084
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