For 53 mg/mL and you want 100 mL so 53 x 100 = 5300 mg of the salicylate, place in a 100 mL volumetric flask, add water and make to the mark on the volumetric flask.
0.02M FeCl3. That means 0.02 mols/L or 0.002 mols/100 mL. How much is 1 mole?
mols = g/molar mass. You know molar mass and mols you need, solve for grams. Place that many grams in a 100 mL volumetric flask and make to the mark with distilled water.
You can follow the same directions as the FeCl3 but that will be hard to do since HCl is a gas. The best way to do that is to use some HCl already made up and dilute it. You will need to know the concn of the stronger solution.
Then mL1 x M1 = mL2 x M2.
Say you had some 1 M stuff, then
mL1 x 1M = 100 mL x 0.05M
Solve for mL1 you need of the 1M.
We are asked to prepare a 100 ml solution with the following 3 concentrations:
53.00 mg/ml sodium salicylate, 0.020 M FeCl3, and 0.050 M HCl.
Then, we are going to take the absorbance at 520 nm.
What is the best way to prepare the 100 ml solution ?
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