To determine which wave has the lowest frequency, we use the formula for frequency \( f \), which is given by:
\[ f = \frac{v}{\lambda} \]
where:
- \( v \) is the wave speed,
- \( \lambda \) is the wavelength.
From the table, we can calculate the frequency for each wave:
-
Wave L: \[ f_L = \frac{600 , \text{m/s}}{120 , \text{m}} = 5 , \text{Hz} \]
-
Wave M: \[ f_M = \frac{600 , \text{m/s}}{150 , \text{m}} = 4 , \text{Hz} \]
-
Wave N: \[ f_N = \frac{600 , \text{m/s}}{100 , \text{m}} = 6 , \text{Hz} \]
-
Wave O: \[ f_O = \frac{600 , \text{m/s}}{50 , \text{m}} = 12 , \text{Hz} \]
Now, we compare the frequencies:
- \( f_L = 5 , \text{Hz} \)
- \( f_M = 4 , \text{Hz} \)
- \( f_N = 6 , \text{Hz} \)
- \( f_O = 12 , \text{Hz} \)
The wave with the lowest frequency is Wave M with a frequency of \( 4 , \text{Hz} \).
Thus, the correct response is:
wave M
1 answer