Water spouts from a horizontal pipe 12 meters above the ground. Three meters below the line of the pipe, the water trajectory is at a horizontal distance of 5 meters from the water outlet. How far from the water outlet will the stream of the water hit the ground?

Answer 1

h = 0.5g*t^2 = 3 m.
4.9t^2 = 3
t^2 = 0.612
Tf = 0.782 s. = Fall time.

Dx = Xo*Tf = 5 m.
Xo * 0.782 = 5
Xo = 6.39 m/s = Hor. component of initial velocity.

h = 0.5g*t^2 = 12 m.
4.9t^2 = 12
t^2 = 2.45
Tf = 1.56 s.

Dx = Xo*Tf = 6.39m/s * 1.56s. = 10 m.
From water outlet.