Water of mass 200g and temperature 10digrees Celsius is put in a copper calorimeter of mass 80g. Steam from boiler at a normal pressure is passed into the calorimeter for sometime. The total mass of the calorimeter and contents is 283g. The final temperature of the contents is measured and is T.

Question

Determine:
(i) heat lost by the steam on condensing to water.
(ii) heat lost by condensed water.
(iii) heat gained by the calorimet rer and the cold water.
(iv) the value of T.

Answer 1

(i) heat lost on condensing is Q = mL
=3X2.26X10^3Joules = 6780 Joules

(iv) 0.383X80X(T-10) + 4.186X200X(T-10) = 6780 + 3X4.186X(100-T)

Solve for T

(ii) put the value of T in 2nd term of RHS in the above equation

(iii) Find the Value of LHS by substituting the value of T in the above equation