Asked by Sam
Water is to be pumped to the top of a skyscraper, which is 1270 ft high. What gauge pressure is needed in the water line at the base of the building to raise the water to this height?
Answers
Answered by
Elena
1270 ft = 387 m,
Pressure (Pa) = Density (1000 kg/m3) x Acceleration (9.8m/s2) x Height (m) =
1000•9.8•387 =3.8•10^6 Pa
Pressure (Pa) = Density (1000 kg/m3) x Acceleration (9.8m/s2) x Height (m) =
1000•9.8•387 =3.8•10^6 Pa
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