Water is flowing into a vertical cylindrical tank of diameter 4 m at the rate of 2 m3/min. Find the rate at which the depth of the water is rising. (Round your answer to three decimal places.)

Answer 1

volumetank=PI*2^2*h
dv/dt=4PI* dh/dt

dh/dt=1/2PI m^3/min

Answer 2

the area of the water's surface is 4π m^2

since volume = area * thickness, the thickness is changing by

2/(4π) = 1/(2π) m/min