Water is drained out of tank, shaped as an inverted right circular cone that has a radius of 16cm and a height of 8cm, at the rate of 4 cm^3/min. At what rate is the depth of the water changing at the instant when the water in the tank is 6 cm deep? Show all work and include units in your answer. Give an exact answer showing all work and include units in your answer.

asked by Mel

9 years ago

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1 answer

hint
dh/dt * surface area = 4 cm^3/min

answered by Damon

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Question

Water is drained out of tank, shaped as an inverted right circular cone that has a radius of 16cm and a height of 8cm, at the rate of 4 cm^3/min. At what rate is the depth of the water changing at the instant when the water in the tank is 6 cm deep? Show all work and include units in your answer. Give an exact answer showing all work and include units in your answer.

1 answer

hint
dh/dt * surface area = 4 cm^3/min

Damon · Answer

hint dh/dt * surface area = 4 cm^3/min