Water flows with a speed of 2.5 m/s through a section of hose with a cross-sectional area of 0.0084 m^2. Further along the hose the cross-sectional area changes, and the water speed is reduced to 1.1 m/s. Calculate the new cross-sectional area.

Answer 1

since the volume flow rate of the water is constant (why?) and m^2 * m/s = m^3/s
A*1.1 = .0084 * 2.5

Answer 2

unit?

Answer 3

how to make it

Answer 4

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