integral of (500-3t)
= 500 t - 1.5 t^2
at t = 13, integral = 500(13)-1.5(169)
= 6500 - 253.5
= 6246.5 liters
Water flows from a storage tank at a rate of 500 − 3t liters per minute. Find the amount of water that flows out of the tank during the first 13 minutes.
1 answer