area = A = pi D^2/4 = pi (.0277^2)/4 = 6.03*10^-4 m^2
Q = volume/second 25 * 10^-3 m^3 / 84 s
= .298 *10^-3 m^3/s
A v = Q
v = Q/A = .298*10^-3/6.03*10^-4
= .0494 *10^1 = .494 m/s
Water flowing through a garden hose of diameter 2.77 cm fills a 25.0-L bucket in 1.40 min.
(a) What is the speed of the water leaving the end of the hose?
Answer in m/s
(b) A nozzle is now attached to the end of the hose. If the nozzle diameter is one-third the diameter of the hose, what is the speed of the water leaving the nozzle?
Answer in m/s
1 answer