They want you to use
C= 4200 J/ kg*degC for the specific heat and
g = 10 m/s^2 for the acceleration of gravity
H = 84 m is the height
Energy conservation tells you that
C*(deltaT) = g*H
Solve for deltaT, in degrees C
Water falls from a height of 84 m. Assuming that all the energy is converted into heat, the rise in temperature of water will be (4200 J/(kg °C) and g=10 m/s2)?
4 answers
0.2
C∆T=gH
C of water=4200 J/kg°C
4200(T2-T1)= 10×84
T2-T1=10×84/4200
T2-T1=0.2°C
C of water=4200 J/kg°C
4200(T2-T1)= 10×84
T2-T1=10×84/4200
T2-T1=0.2°C
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