To solve the logarithmic problems, we can use the definition of logarithms. The logarithm \( \log_b(a) = c \) means that \( b^c = a \).
Let’s solve each one:
a. \( \log_2(16) \)
We know that \( 16 = 2^4 \). Therefore, \( \log_2(16) = 4 \).
b. \( \log_7(49) \)
We know that \( 49 = 7^2 \). Therefore, \( \log_7(49) = 2 \).
c. \( \log_4(64) \)
We can express \( 64 \) as \( 4^3 \) since \( 4 = 2^2 \) and \( 64 = 2^6 \). Thus, \[ \log_4(64) = \log_4(4^3) = 3 \].
d. \( \log_3(27) \)
We know that \( 27 = 3^3 \). Therefore, \( \log_3(27) = 3 \).
e. \( \log_6(216) \)
We know that \( 216 = 6^3 \). Therefore, \( \log_6(216) = 3 \).
Here are the results:
a. \( \log_2(16) = 4 \)
b. \( \log_7(49) = 2 \)
c. \( \log_4(64) = 3 \)
d. \( \log_3(27) = 3 \)
e. \( \log_6(216) = 3 \)
Please let me know if you need further assistance!