To solve for w in terms of x, we can set up a system of equations based on the information given:
w = k*x + m*x^2
Using the first set of data: x=3, w=18
18 = 3k + 9m
Using the second set of data: x=5, w=169
169 = 5k + 25m
Now we can solve these two equations simultaneously to find the values of k and m.
From equation 1:
18 = 3k + 9m
=> 2k + 6m = 12
From equation 2:
169 = 5k + 25m
=> k + 5m = 33
Solving these two equations simultaneously, we get:
k = 3
m = 2
Therefore, w = 3x + 2x^2 = x(3+2x)
So, w in terms of x is w = x(3+2x)
W varies partly as x and partly as the x square of x when x =3, w=18, and when x=5, w=169. Find w interm of x
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