Volume of Spheres Quick Check 5 of 55 of 5 Items Question Kairay created a sculpture by forming a hemisphere with a radius of 20 inches and then removing a hemisphere with a radius of 15 inches from it. Calculate the volume of his sculpture. Use 3.14 as an approximation for pi. Round your answer to the nearest whole number.(1 point) Responses 7,065 in.3 7,065 inches cubed 19,363 in.3 19,363 inches cubed 9,682 in.3 9,682 inches cubed 16,747 in.3

1 answer

To find the volume of Kairay's sculpture, we need to calculate the volume of the larger hemisphere and subtract the volume of the smaller hemisphere.

The volume \( V \) of a hemisphere is given by the formula:

\[ V = \frac{2}{3} \pi r^3 \]

Step 1: Calculate the volume of the larger hemisphere with a radius of 20 inches.

Using \( r = 20 \) inches:

\[ V_{large} = \frac{2}{3} \pi (20)^3 \] \[ = \frac{2}{3} \pi (8000) \] \[ = \frac{16000}{3} \pi \]

Using \( \pi \approx 3.14 \):

\[ V_{large} = \frac{16000}{3} \times 3.14 \approx \frac{16000 \times 3.14}{3} \approx \frac{50240}{3} \approx 16747 \text{ cubic inches} \]

Step 2: Calculate the volume of the smaller hemisphere with a radius of 15 inches.

Using \( r = 15 \) inches:

\[ V_{small} = \frac{2}{3} \pi (15)^3 \] \[ = \frac{2}{3} \pi (3375) \] \[ = \frac{6750}{3} \pi \]

Using \( \pi \approx 3.14 \):

\[ V_{small} = \frac{6750}{3} \times 3.14 \approx \frac{6750 \times 3.14}{3} \approx \frac{21195}{3} \approx 7065 \text{ cubic inches} \]

Step 3: Calculate the volume of the sculpture.

Now, we subtract the volume of the smaller hemisphere from the volume of the larger hemisphere:

\[ V_{sculpture} = V_{large} - V_{small} \] \[ = 16747 - 7065 = 9682 \text{ cubic inches} \]

Thus, the volume of Kairay's sculpture is approximately:

9,682 cubic inches.

The correct response is 9,682 in.³.