To find the volume of the basketball, we can use the formula for the volume \( V \) of a sphere:
\[ V = \frac{4}{3} \pi r^3 \]
where \( r \) is the radius of the sphere. The diameter of the basketball is given as 9 inches, so we need to first find the radius:
\[ r = \frac{\text{diameter}}{2} = \frac{9 \text{ inches}}{2} = 4.5 \text{ inches} \]
Next, we can calculate the volume using \( \pi \approx 3.14 \):
\[ V = \frac{4}{3} \times 3.14 \times (4.5)^3 \]
First, calculate \( (4.5)^3 \):
\[ (4.5)^3 = 4.5 \times 4.5 \times 4.5 = 91.125 \]
Now substitute this value back into the volume formula:
\[ V = \frac{4}{3} \times 3.14 \times 91.125 \]
Calculate \( \frac{4}{3} \times 3.14 \):
\[ \frac{4}{3} \times 3.14 \approx 4.1867 \]
Now multiply this by \( 91.125 \):
\[ V \approx 4.1867 \times 91.125 \approx 381.5 \]
So the volume of the basketball is approximately 381.5 in³.
Thus, the answer is:
381.5 in.³
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