Volume of Spheres Practice

Complete this assessment to review what you've learned. It will not count toward your grade.
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Question
How much chocolate is in a spherical chocolate truffle with a radius of 12 mm? Use 3.14 as an approximation for pi. Round your answer to the nearest hundredth, if necessary.(1 point)
mm3
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To find the volume of a sphere, you can use the formula:

\[ V = \frac{4}{3} \pi r^3 \]

Where \( V \) is the volume, \( \pi \) is approximately 3.14, and \( r \) is the radius.

Given the radius \( r = 12 \) mm, you can substitute the values into the formula:

\[ V = \frac{4}{3} \times 3.14 \times (12)^3 \]

Now calculate \( (12)^3 \):

\[ 12^3 = 12 \times 12 \times 12 = 144 \times 12 = 1728 \]

Now plug this value into the volume formula:

\[ V = \frac{4}{3} \times 3.14 \times 1728 \]

Calculating \( \frac{4}{3} \times 3.14 \):

\[ \frac{4 \times 3.14}{3} = \frac{12.56}{3} \approx 4.18667 \]

Now multiply by 1728:

\[ V \approx 4.18667 \times 1728 \approx 7225.03 \]

Rounding to the nearest hundredth, the volume is:

\[ \boxed{7225.03 \text{ mm}^3} \]

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