To find the volume of the cylinder with the same dimensions as the sphere whose volume is given as 60 cubic meters, we first need to determine the radius of the sphere.
The formula for the volume of a sphere is:
\[ V = \frac{4}{3} \pi r^3 \]
Where \( V \) is the volume and \( r \) is the radius. Given that:
\[ \frac{4}{3} \pi r^3 = 60 \]
To find \( r^3 \), we rearrange the equation:
\[ r^3 = \frac{60 \times 3}{4\pi} = \frac{180}{4\pi} = \frac{45}{\pi} \]
Now we calculate \( r \):
\[ r = \left(\frac{45}{\pi}\right)^{1/3} \]
Now that we have the radius, we'll consider a cylinder with the same base radius and height as the diameter of the sphere.
The diameter \( d \) of the sphere is:
\[ d = 2r = 2 \left(\frac{45}{\pi}\right)^{1/3} \]
The height \( h \) of the cylinder is equal to the diameter of the sphere:
\[ h = d = 2 \left(\frac{45}{\pi}\right)^{1/3} \]
The volume \( V \) of the cylinder is given by the formula:
\[ V = \pi r^2 h \]
Substituting \( r \) and \( h \) into the formula:
\[ V = \pi r^2 (2r) = 2\pi r^3 \]
Now we substitute \( r^3 \) from our previous calculation:
\[ V = 2\pi \left(\frac{45}{\pi}\right) = 90 \]
Thus, the volume of the cylinder with the same dimensions as the sphere is:
\[ \boxed{90 \text{ cubic meters}} \]