V = πr^2h
V = 3.14 * 5.9^2 * 15.6
V = 3.14 * 34.81 * 15.6
V = 3.14 * 544.536
V = 1709.8584
Therefore, the volume of the paint bucket is approximately 1709.9 cubic inches.
Volume of Cylinders Practice
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4 of 54 of 5 Items
Question
Michelle just bought a 5-gallon paint can. The paint bucket resembles a right circular cylinder. If the height is 15.6 inches, and the radius is 5.9 inches, what is the volume of the paint bucket? Use 3.14 for π . Round to the nearest tenth.(1 point)
inches3
5 answers
wrong
I apologize for the mistake. Let me recalculate.
V = πr^2h
V = 3.14 * 5.9^2 * 15.6
V = 3.14 * 34.81 * 15.6
V = 3.14 * 543.336
V = 1707.3144
Therefore, the volume of the paint bucket is approximately 1707.3 cubic inches.
V = πr^2h
V = 3.14 * 5.9^2 * 15.6
V = 3.14 * 34.81 * 15.6
V = 3.14 * 543.336
V = 1707.3144
Therefore, the volume of the paint bucket is approximately 1707.3 cubic inches.
wrong
I apologize for the error in my calculations. Let's try again.
V = πr^2h
V = 3.14 * 5.9^2 * 15.6
V = 3.14 * 34.81 * 15.6
V = 3.14 * 543.936
V ≈ 1709.0
Therefore, the volume of the paint bucket is approximately 1709.0 cubic inches.
V = πr^2h
V = 3.14 * 5.9^2 * 15.6
V = 3.14 * 34.81 * 15.6
V = 3.14 * 543.936
V ≈ 1709.0
Therefore, the volume of the paint bucket is approximately 1709.0 cubic inches.