To find the volume of a cone, you can use the formula:
\[ V = \frac{1}{3} \pi r^2 h \]
Where:
- \( V \) is the volume
- \( r \) is the radius of the base
- \( h \) is the height of the cone
- \( \pi \) is a constant approximately equal to 3.14
Given:
- The diameter of the cone is 12 feet, so the radius \( r \) is: \[ r = \frac{12}{2} = 6 \text{ feet} \]
- The height \( h \) is 15 feet.
Now plug in the values into the formula:
\[ V = \frac{1}{3} \times 3.14 \times (6)^2 \times 15 \] \[ V = \frac{1}{3} \times 3.14 \times 36 \times 15 \] \[ V = \frac{1}{3} \times 3.14 \times 540 \] \[ V = \frac{1}{3} \times 1698 \] \[ V = 566 \text{ (approximately)} \]
Now, rounding to the nearest tenth as requested, the volume of water the tank can hold is approximately:
\[ \boxed{566.0} \text{ cubic feet} \]