use Ideal Gas Law Equation
p1V1/T1 = p2V2/T2
Volume of 1200 L of helium at 4000 Pa is heated from 45.0°C to 75.0°C increasing the pressure to 6000 Pa. What is the resulting volume of gas?
2 answers
p1•V1/T1 = p2•V2/T2
V1 =1200 L =1200•10^-3 m^3
T1 =273 +45 = 318 K
T2 =273 +75 = 348 K
V2 = p1•V1•T2/p2•T1
V1 =1200 L =1200•10^-3 m^3
T1 =273 +45 = 318 K
T2 =273 +75 = 348 K
V2 = p1•V1•T2/p2•T1