You didn't type in part of the question; i.e., you meant to say that the molar mass was 180. Also, note that the perentages DO NOT add up to 100% and they must. Perhaps that 5.45% O really is 54.5
Take a 100 g sample which gives you 40.9 g C, 4.58 g H, 54.5 g O.
Convert to mols.
mols C = 40.9/12 = about 3.4
mols H = 4.58/1 = about 4.6
mols O = 54.5/16 = 3.4
Now to find the empirical formula. Divide all by the smallest; i.e.,
mols C - 3.4/3.4 = 1
mols H = 4.6/3.4 = 1.35
mols O = 3.4/3.4 = 1.
So the empirical formula, in whole numbers, is C3H4O3 and the empirical mass is 88,
molar mass i= (empirical mass x whole number)
180 = 88*whole number. You solve for the whole number
Post your work if you need further assistance.
Vitamin c,which may or may not be affective in preventing cold,is an organic compound containing carbon,hydrogen and oxygen.analysis of a carefully purified sample give c=40.9%,h=4.58%,o=5.45%.from another experiement to be 180.from these data,determine:(a)the empirical formula of vitamin c.(b)the molecula formula.
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