Visualize the structural formula of each of the following hydrocarbons. Which hydrocarbon has a double bond in its carbon skeleton?

Question

C2H4
C3H8
C2H2
C2H6

Answer 1

To visualize the structural formulas of the given hydrocarbons, let’s break down each molecule:

1. C2H4 (Ethene): This is an alkene with a double bond between the two carbon atoms. The structure can be represented as:

   H2C=CH2
   

   Here, the double bond is present between the two carbon atoms.

2. C3H8 (Propane): This is an alkane and does not contain any double bonds. Its structural formula is:

   CH3-CH2-CH3
   

3. C2H2 (Ethyne): This is also an alkane with a triple bond between the two carbon atoms. The structure can be represented as:

   H-C≡C-H
   

   There are no double bonds here, but a triple bond.

4. C2H6 (Ethane): This is another alkane that has no double bonds. Its structural formula is:

   CH3-CH3
   

Summary:

• C2H4 (Ethene) has a double bond in its carbon skeleton.
• C3H8 (Propane), C2H2 (Ethyne), and C2H6 (Ethane) do not have double bonds in their carbon skeletons.

Thus, the hydrocarbon with a double bond is C2H4 (Ethene).