Visit: VIRTUAL LAB: Textbook Style Limiting Reagents Problems on Chem collective
Windows and Macintosh users: Please use Firefox or Chrome web browser.
The simulation will run on most laptops, desktops and touch-enabled devices such as tablets, iPads or phones. (Note: Touch enabled support is still under development, and may be a bit 'clunky').
Please use the HELP tab for information on how to pour one solution to another.
1.) Use the virtual lab to answer the questions below.
a. The solution labeled "1.00g NaCl" contains 1.00g of NaCl dissolved in water. Use the solution viewer to determine the number of grams of Na+ and Cl- in the solution, and confirm that these add to 1.00g.
b. The solution labeled "1.00g AgNO3" contains 1.00g of solid AgNO3. Add 100ml of water to this solution. Use the solution viewer to determine the number of grams of Ag+ and NO3- in the solution.
c. Now add the 1.00g of solid AgNO3 to the 1.00g solution of NaCl. Write down the mass of each species in solution and the mass of solid AgCl formed. Confirm that the amounts of these species are consistent with what you say in parts (2) and (3).
Table 1: Mass of each species after reaction (2.5 marks)
Species Mass (g)
Na+
Cl-
NO3-
Ag+
AgCl(s)
2.) The solution labeled "Solution 1" in the virtual lab stockroom contains 2.00 grams of Sodium Chloride.
a. How many grams of Silver Nitrate must be added to the solution to completely react with Sodium Chloride according to the reaction above? Show your calculations. _____ (1 mark)
b. Use the virtual lab to add that amount of Silver Nitrate to the solution. Check to make sure the reaction was complete, by making sure the amount of Ag+ and Cl- in the solution are both less than 0.01g.
3.) The solution labeled "Solution 2" in the virtual lab stockroom contains 3.00 grams of AgNO3.
If excess NaCl is added to the solution, how many grams of AgCl(s) will be formed? Show your calculations. _____
4.) Use the virtual lab to check your answer to 3 (a). Explain the laboratory procedure you used to perform this check.