Write the equation. It tells you that 1 mole NaOH = 1 mole acetic acid.
CH3COOH + NaOH ==> CH3COONa + H2O
moles NaOH = M x L = ??
Since the ratio of acetic acid to NaOH is 1:1, then moles acetic acid = moles NaOH.
Finally, M acetic acid = moles acetic acid/L acetic acid. You know moles and L acetic acid, solve for M.
Vinegar is a dilute solution of acetic acid. What is the concentration of acetic acid in the vinegar if 26.5 mL of NaOH at 0.250 M are required to neutralize 10.0 mL of vinegar?
1 answer
1 answer