Villages p, q and r are situated as follows, p is 15km due north of q and the bearings of p and q are 50 degree and 80 degree respectively. Calculate the distance of r from p and q

Answer 1

I appears that you have a triangle PQR , with PQ = 15 km,
and angle P = 50°, angle Q = 80°
A quick mental calculation gives us angle R = 50° , making the triangle isosceles.
So without any work, QR = 15 km

by the sine law:
PR/sin80 = 15/sin50
PR = 15sin80/sin50
= ...

let me know if I misunderstood your description.

Answer 2

Village P Q and R are situated as follows .P is 15km due north of Q and the bearing of P and Q from R are 50° and 80° respectively . calculate to the nearest 0.5 km the distance of R from P and Q

Answer 3

IN ABC C=53°,b=3.56,c=4.28