Villages A,B,C,D are such that B is 4km due east of A, C is 3km due south of B and D is 4km S 50 W from C.calculate the distance and bearing of A from D.

Answer 1

Put A at origin

Dx = 4 - 4 sin 50 = .9358

Dy = -3 -4 cos 50 = -5.571

from origin to D (w will reverse later)
tan angle east of south = .9358/5.571
angle east 0f south = 9.54 degrees east of south
Reversed for bearing from D to A that is 9.54 degrees west of north
or 360 - 9.54 = 350.5 degrees true on chart

distance = sqrt(.9358^2 + 5.571^2)
= 5.65 km

Answer 2

The DIAGRAM