Surface area of the box = 2(lb + bh + lh)
Where l = 20 cm, b = 30 cm, h = 8 cm
=> A = 2[(20)(30) + (30)(8) + (20)(8)]
= 2(600 + 240 + 160)
= 2(1000)
= 2000 cm^2
= 0.2 m^2
Hence, she has enough paper.
Vidya wants to cover a gift box whose dimensions are 20 cm,30cm and 8cm. She has a piece of paper of area 1 metre square. Will she be able to cover the gift? Explain.
8 answers
While finding the surface area of the box is helpful, it might not always be enough. You have to make sure that each dimension is such that the paper will actually fit.
In this case, all is well, since the longest dimension is 30cm, well within the 100cm length of the paper.
Then, wrapping it around the box, there is enough paper, since the girth is just 2(8+25) = 66cm, enough to allow the paper to wrap around and still have enough to overlap for taping.
I'm sure you can some up with a scenario where the area of the box is less than 1m^2 and still the paper will not do for wrapping it up.
In this case, all is well, since the longest dimension is 30cm, well within the 100cm length of the paper.
Then, wrapping it around the box, there is enough paper, since the girth is just 2(8+25) = 66cm, enough to allow the paper to wrap around and still have enough to overlap for taping.
I'm sure you can some up with a scenario where the area of the box is less than 1m^2 and still the paper will not do for wrapping it up.
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