Asked by Shelby
                Very hot zinc will react with steam to form zinc oxide and hydrogen.  What volume of steam would be necessary in order to use up 20.0 g of zinc completely?  What volume of hydrogen would be produced in this case?
I NEED HELP WITH THIS!!..PLEASE = )
            
        I NEED HELP WITH THIS!!..PLEASE = )
Answers
                    Answered by
            DrBob222
            
    1.Write the equation.
2. Convert 20.0g Zn to mols Zn.
3. Using the equation convert mols Zn to mols H2O (steam).
4. Convert mols H2O (steam) to volume using mols x 22.4 L/mol = ?? L.
The part on hydrogen is a separate question but is worked by the same principles.
    
2. Convert 20.0g Zn to mols Zn.
3. Using the equation convert mols Zn to mols H2O (steam).
4. Convert mols H2O (steam) to volume using mols x 22.4 L/mol = ?? L.
The part on hydrogen is a separate question but is worked by the same principles.
                    Answered by
            Shelby
            
    I did step two and got .3057 but how do i do step three?
    
                    Answered by
            nadeem
            
    when temp  700-900c zinc metal (99.99%) fumes quenching with super heated steam (190-200c)not ceturated steam, zinc react with oxygen make zinc oxide and hydrogen librated, u have need 55.5 gram water for 20g zinc metal in libority micro test
malik nadeem
classic chemicals lahore pakistan
    
malik nadeem
classic chemicals lahore pakistan
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