I know that sometimes finding the solution is tricky, but surely just taking the derivatives is easy, no?
y = c1-cos(x+c2)
y' = -sin(x+c2)
y" = -cos(x+c2)
(y")^2 + (y')^2 - 1 = 0
sin^2+cos^2 = 1, right?
Verify whether the given equation(y=c1-cos(x+c2)) is a solution to this equation[(d^2y/dx^2)^2 + (dy/dx)^2 - 1 = 0].
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