1.
y = x^2+1
This is always positive, with its minimum value at x=0, where y=1. The range is [1,∞0, but that's not where it is increasing.
Now, the question asks about the reciprocal function z = 1/y
z = 1/(x^2+1)
Where y increases, z decreases, and vice versa. So, z is increasing on (-∞, 0), answer B
2. OK
3. None of the above. Would be C, but the horizontal is y = 1/2. I assume you wanted (x-4)/(2x+1)
4. vertical at x=2 means C or D
horizontal at y=1 keeps C or D
intercept at (3,0) means D
increasing keeps D
so, D.
5. D = x not 2/3 means A or B
y-intercept at (0,1/2) means B.
So, B.
Verify these answers :]
Would be thankies~
1. Determine the intervals in which the reciprocal function of f(x)= x^2+1 is increasing.
a) (0,∞)
b) (-∞, 0)
c) (-∞,∞)
d) (1,∞)
Answer: D
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2. Determine the point(s) where f(x)=2x^2-1 and its reciprocal function intersect.
a) (1,1)
b) (-1,1)
c) (1,1) and (-1,1)
d) (1,1), (-1,1) and (0,-1)
Answer:D
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3. Identify the vertical and horizontal asympototes of f(x)=x-4/2x+1
a)vertical x=4, horizontal:y=-1/2
b)vertical x=4, horizontal:y=1/2
c)vertical x=-1/2, horizontal:y=-1/2
d)vertical x=1/2, horizontal:y=-1/2
Answer: A
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4. State the equation of the rational function that meets these conditions:
-vertical asympotote at x=2
-Horizontal asympotote at y=1
-increases on each interval of its domain
-x-intecept is (3,0)
a) y=x+3/x+2
b) y=x-3/x+2
c) y=x+3/x-2
d) y=x-3/x-2
Answer: A
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5. state the equation of f(x) is D= [XER|x≠2/3] and the y-intercept is (0,1/2).
a) f(x)=2x+1/3x-2
b) f(x)=x-1/3x-2
c) f(x)=x+1/3x+2
d) f(x)=2x+1/3x+2
Answer is B?
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4 answers