Verify that the point ( square root(31)/7, -3square root(2)/7 ) lies on the graph of the unit circle. If it does, use symmetry to find three other points that also lie on the graph of the unit circle.

Question

(direction - Type ordered pairs).

PS: The -3 is outside the square root ( but it's in the numerator). 2 in inside the square root. 7 is not included in the square root(7 is the denominator). 31 is inside the square root and 7 is not included in the square root (7 is the denominator).

Please show the steps & answer because I have to do so many. Thank You.

Answer 1

All you need to do is show that x^2+y^2=1. Don't forget your Algebra I now that you're in pre-cal!

(√31/7)^2 = 31/49
(-3√2/7)^2 = 18/49

Looks like they add up to 1, so the point is on the unit circle.

Answer 2

This is very, very similar to one I already helped you with. Please try them yourself. It does not do you any good to have us do all the problems for you. The idea is that we can help, but not do virtually the same problem over and over for you.
http://www.jiskha.com/display.cgi?id=1469345829