what's the problem? Just plug and chug:
f(g) = ln(g-1) = ln(1+e^x-1) = ln(e^x) = x
g(f) = 1+e^f = 1 + e^(ln (x-1)) = 1 + x-1 = x
Just keep in mind the definition of a logarithm:
e^lnx = x
ln e^x = x
verify that the functions of f and g are inverse of each other by showing that f(g(x))=x and g(f(x))=x; f(x)=In(x-1),g(x)=1+e^x
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