y = x - 1/x
y' = 1 + 1/x^2
So, to verify that it is a solution, just plug and chug:
xy' + y = x(1 + 1/x^2) + x - 1/x = x + 1/x + x - 1/x = 2x
Verify that the function y(x)= x - (1/x) is a solution to the differential equation, xy'+ y= 2x
I have absolutely no clue what to do with that + y
Please help :c
1 answer