Verify:

Tan u + sec u-1 / tan u - sec u+1 = tan u + sec u

3 answers

You have

(tan+sec-1)/(tan-(sec-1))

multiply top and bottom by tan+sec-1 and you have

(tan+sec-1)^2/(tan^2-(sec-1)^2)

tan^2+sec^2+1+2tan*sec-2tan-2sec)/(tan^2-sec^2+2sec-1)

(sec^2+tan*sec-tan-sec)/(sec-1)

(tan+sec)(sec-1)/(sec-1)

tan+sec
Two steps after multiplying the top and bottom, why does tan become 2tan on top
tan does not become 2tan

expand (a+b-1)^2 and you will see the 2's, just as

(a+b)^2 = a^2 + 2ab + b^2
Similar Questions
    1. answers icon 1 answer
    1. answers icon 1 answer
    1. answers icon 2 answers
  1. How do you verify inverses?the question is y=3x-3... we know how to make an inverse but how do you verify it using composition?
    1. answers icon 1 answer
more similar questions