you can do this. You have the x,y component of them added.
magnitude=sqrt(x^2+y^2)
angle=arctan y/x
Vector V1 is 6.29 units long and points along the negative x axis. Vector V2 is 4.23 units long and points at +35.0° to the +x axis.
(a) what is V1x & V1y
(b) what is the magnitude & direction (degrees)
5 answers
but whats my X & Y
V1x=-6.29 V2y=0
V2x=4.23cos35 V2y=4.23Sin35
Do you need a tutor? Surely there are example problems in the text. This is very basic problems.
V2x=4.23cos35 V2y=4.23Sin35
Do you need a tutor? Surely there are example problems in the text. This is very basic problems.
for some reason the 6.29 for vx1 keeps telling me i'm wrong..thanks a lot for the help! i obviously suck at this!
it is in the NEGATIVE Direction.
2 answers