Vector has a magnitude of 136 units and points 35.0 ° north of west. Vector points 69.0 ° east of north. Vector points 19.0 ° west of south. These three vectors add to give a resultant vector that is zero. Using components, find the magnitudes of (a) vector and (b) vector .

Question

I have drawn a diagram of the vectors but besides that im stumped

Answer 1

add up the north components (y axis)
add up the east components (x axis)

take the square root of the sum of the squares for the magnitude

Tan theta = total y/total x
but that theta is the math theta, counterclockwise from x axis

for compass angle -- > 90 - theta

Answer 2

Sorry, I made that too hard.
the two unknown vectors result in a vector that is equal and opposite to the first one
so
B + C is 136 units 35 deg south of east

|B|^2 + |C|^2 = 136 ^2

Bx + Cx = 136 cos 35

By + Cy = -136 sin 35

Bx = |B| sin 69
By = |B| cos 69

Cx = -|C| sin 19
Cy = -|C| cos 19