in quadrant 2 ---> x negative, y +
reference angle = 180 -125 = 55 above -x axis
Bx = -21.50 cos 55
By = +21.50 sin 55
Vector B has a magnitude of 21.50. Its direction measured counterclockwise from the x axis is 125.0°. Find its vector components. (Assume that the +x axis is to the right and the +y axis is up along the page. Also, assume
B
is in the x-y plane.)
2 answers
B = 21.5[125o].
X = 21.5*Cos125. = -12.33.
Y = 21.5*sin125 = 17.61.
X = 21.5*Cos125. = -12.33.
Y = 21.5*sin125 = 17.61.
0 answers