Vapour pressure of benzene and toluene are 0.9bar and 0.85bar. 7.8g of benzene is added to 180g of toluene. To find the vapour pressure of the resultant solution

Answer 1

The partial vapor pressure of a component in a mixture is equal to the vapor pressure of the pure component at that temperature multiplied by its mole fraction in the mixture. ... The total vapor pressure of the mixture is equal to the sum of the individual partial pressures

first, find the mole fractions.
Moles of benzene, moles toluene. Then, add to get total moles
Then, partial vp of toulene= .85*molestoulene/totalmoles
and same method to get vp of benzene.
Add the two partial vp to get total solution vp

Answer 2

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