Given the difference quotient:
Δy/Δx = -2(8.001) + 16 / 0.001
This simplifies to:
Δy/Δx = -16.002 + 16 / 0.001
Δy/Δx = -0.002 / 0.001
Δy/Δx = -2
This indicates that the equation of y=f(x) is a linear function with a slope of -2. Since the IROC is the same as the slope of the function, the approximate IROC at x=8 is also -2.
The value of h is 0.001.
To find the ordered pair for the tangent point on f(x), we need to calculate the y-coordinate at x=8. Since the slope of the function is -2, we know that the equation of the line passing through (8,f(8)) with slope -2 is:
y = -2x + b
To find the y-coordinate, we substitute x=8 into the equation:
f(8) = -2(8) + b
f(8) = -16 + b
Since f(8) is unknown, we can't determine the exact ordered pair without further information or calculations.
Values for x and h have been substituted into the difference quotient produce delta y over delta x= -2(8.001)+16 over 0.001 state the equation of y=f(x) the approximate IROC at x=8 the value of h and the ordered pair for the tangent point on f(x)
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