To determine whether the equation \(-12(x - 3) - 52 = -16\) has one solution, infinitely many solutions, or no solution, we need to simplify it.
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Distribute \(-12\):
\[ -12(x - 3) = -12x + 36 \] So the equation becomes: \[ -12x + 36 - 52 = -16 \]
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Combine like terms:
\[ -12x + 36 - 52 = -16 \implies -12x - 16 = -16 \]
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Next, add 16 to both sides of the equation:
\[ -12x - 16 + 16 = -16 + 16 \implies -12x = 0 \]
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Now, divide both sides by -12:
\[ x = 0 \]
Since we arrived at a specific value for \(x\) (which is \(x = 0\)), this indicates that the equation has one solution.
Thus, the correct justification is: It has one solution because the solution is in the form \(x = a\). The solution is \(x = 0\).