To model the situation with a two-variable inequality, we can let:
- \( x \) represent the number of adult tickets purchased.
- \( y \) represent the number of children's tickets purchased.
The cost of adult tickets is $15 each, and the cost of children's tickets is $12 each, and the family wants to spend a maximum of $150. Thus, we can write the inequality as follows:
\[ 15x + 12y \leq 150 \]
Next, we also need to consider the contextual constraints. Since the number of tickets cannot be negative, we have the following constraints:
- \( x \geq 0 \) (number of adult tickets cannot be negative)
- \( y \geq 0 \) (number of children's tickets cannot be negative)
Now, we can evaluate the given points to see which ones satisfy the inequality \( 15x + 12y \leq 150 \) and the constraints:
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Point (10, 5):
- \( 15(10) + 12(5) = 150 + 60 = 210 \) (not viable)
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Point (−3, 5):
- Invalid since \( x \) cannot be negative (not viable)
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Point (2, 5):
- \( 15(2) + 12(5) = 30 + 60 = 90 \) (90 ≤ 150; viable)
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Point (3, 4.5):
- \( 15(3) + 12(4.5) = 45 + 54 = 99 \) (99 ≤ 150; viable)
The viable solutions from the list are (2, 5) and (3, 4.5). However, since the constraints state that \( x \) and \( y \) must be whole numbers (you can't have a fraction of a ticket), the only viable option that fits whole numbers is (2, 5).
Thus, the answer is (2, 5).