Using these numbers, 2 4/9, 2 5/9, 2 6/9, 2 8/9,

3, 3 1/9, 3 3/9, 3 4/9 & 3 5/9. Build a square where the sum of every horizontal, vertical, and diagonal row is 9.
The square has 3 rows across & 3 rows down for a total of 9 small blocks.

2 answers

The standard 3by3 magic square is

8 1 6
3 5 7
4 9 2 --> notice ever row, column and diagonal adds up to 15 for a total of 45.
Any 9 numbers in an arithmetic sequence can be arranged in the above order and you would have a magic square with the properties you want.

change all your mixed fractions to a usable form
22/9 , 23/9 ... , 32/9

to see that they are "consecutive" with 1/9 as the common difference, with the exception from 24/9 to 26/9 and again from 28/9 to 30/9

This really messes it up. If it is as typed, I don't think it is possible to do it
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