Assuming the two walls meet at a right angle,
x+y = 30
a = xy = x(30-x)
this is just a parabola, with vertex at x=15. As usual, the area is a square.
You can take the derivative if you want, but no calculus needed here...
using the two existing corner sides of an existing wall, what is the maximum rectangular area that can be fenced by a fencing material 30 ft long?
3 answers
225
just testing this account after a year