One simple way to do this is calculate how many moles of HBr are in 1ml
Moles=.001L/22.4L
So, you have the number of moles of HBr. Since Br2 was used to make it, it must be 1/2 that number of moles. convert that to grams.
Using the reaction below, calculate how many grams of bromine gas are necessary to produce 1.00mL of hydrogen bromide gas at STP.
H`2 + Br`2 -> 2 HBr
where `2 is a subscript two.
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