Asked by t
Using the quadratic formula, find the solution to x^2−6x−16=0
.(1 point)
Responses
x=8
, x=−2
x equals 8 , x equals negative 2
x=8
, x=−8
x equals 8 , x equals negative 8
x=8
x equals 8
x=−2
.(1 point)
Responses
x=8
, x=−2
x equals 8 , x equals negative 2
x=8
, x=−8
x equals 8 , x equals negative 8
x=8
x equals 8
x=−2
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To solve the quadratic equation \(x^2 - 6x - 16 = 0\) using the quadratic formula, we start with the general form:
\[
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\]
In your equation, \(a = 1\), \(b = -6\), and \(c = -16\).
Now we calculate the discriminant:
\[
b^2 - 4ac = (-6)^2 - 4(1)(-16) = 36 + 64 = 100
\]
Now, we can apply the quadratic formula:
\[
x = \frac{-(-6) \pm \sqrt{100}}{2(1)}
\]
\[
x = \frac{6 \pm 10}{2}
\]
This gives us two solutions:
1.
\[
x = \frac{6 + 10}{2} = \frac{16}{2} = 8
\]
2.
\[
x = \frac{6 - 10}{2} = \frac{-4}{2} = -2
\]
Thus, the solutions to the equation \(x^2 - 6x - 16 = 0\) are:
\[
x = 8 \quad \text{and} \quad x = -2
\]
Therefore, the correct response is:
**x=8, x=−2**
or
**x equals 8, x equals negative 2**.
\[
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\]
In your equation, \(a = 1\), \(b = -6\), and \(c = -16\).
Now we calculate the discriminant:
\[
b^2 - 4ac = (-6)^2 - 4(1)(-16) = 36 + 64 = 100
\]
Now, we can apply the quadratic formula:
\[
x = \frac{-(-6) \pm \sqrt{100}}{2(1)}
\]
\[
x = \frac{6 \pm 10}{2}
\]
This gives us two solutions:
1.
\[
x = \frac{6 + 10}{2} = \frac{16}{2} = 8
\]
2.
\[
x = \frac{6 - 10}{2} = \frac{-4}{2} = -2
\]
Thus, the solutions to the equation \(x^2 - 6x - 16 = 0\) are:
\[
x = 8 \quad \text{and} \quad x = -2
\]
Therefore, the correct response is:
**x=8, x=−2**
or
**x equals 8, x equals negative 2**.
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