Using the quadratic equation above, fill in for a, b, and c.

-___ ± √___^2 -4 (__)(__)
_____________________
2(__)
the options for all blanks are x, 1, 3, or 4

3 answers

To fill in the blanks for the quadratic formula, we first need to understand the general form of a quadratic equation:

\[ ax^2 + bx + c = 0 \]

The corresponding values for the quadratic formula:

\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]

Now we can fill in the blanks using the options provided (x, 1, 3, or 4):

  1. In the formula \( -b \), \( b \) can be either x, 1, 3, or 4. We’ll use the simplest option, which is:

    • Fill in the first blank with: 1
  2. The expression under the square root \( b^2 - 4ac \) requires us to fill in:

    • \( b = 1 \) fills in the second blank: \[1^2\]
    • Choose \( a = 1 \) and \( c = 3 \) for this example.
    • Fill in the third blank with: 3 (for \( c \))
    • Fill in the fourth blank with: 1 (for \( a \))
  3. The denominator \( 2a \):

    • Since we used \( a = 1 \),
    • Fill in the last blank with: 1

Putting this together, your completed quadratic formula will be:

\[ -1 \pm \sqrt{1^2 - 4(1)(3)} \] \[ \frac{-1 \pm \sqrt{1}}{2(1)} \]

So the final filled-in version is:

\[ -1 \pm \sqrt{1^2 - 4 (1)(3)} \] \[ \frac{-1 \pm \sqrt{1}}{2(1)} \]

Keep in mind that there could be other combinations of values for \( a \), \( b \), and \( c \) depending on your specific needs or preferences!

What is one solution of the above quadratic equation?(1 point)
Responses

(-3,0)
(-3,0)

(-4,0)
(-4,0)

(0,3)
(0,3)

(-2,-1)

To find one solution of the quadratic equation given in the form:

\[ -1 \pm \sqrt{1^2 - 4(1)(3)} \]

First, we simplify the expression under the square root:

  1. Calculate \( 1^2 - 4(1)(3) \): \[ 1 - 12 = -11 \]

So, the quadratic equation turns into:

\[ x = \frac{-1 \pm \sqrt{-11}}{2} \]

Since \(\sqrt{-11}\) indicates that the solutions will be complex (involving imaginary numbers), they cannot have real-number solutions. Therefore, none of the provided responses can be solutions to this particular quadratic equation.

However, let's analyze the provided options one more time for any possible connection:

  • (-3, 0): Corresponds to the x-intercept at x = -3 (not a solution to the quadratic).
  • (-4, 0): Corresponds to the x-intercept at x = -4 (not a solution).
  • (0, 3): Corresponds to y = 3 when x = 0 (not a solution).
  • (-2, -1): Also not an x-intercept.

Since the original quadratic equation yields complex solutions, none of the given responses are actual solutions.

If you have any specific additional context or a different equation in mind, please provide it, and I would be happy to assist further!

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